Ask your own question, for FREE!
Physics 12 Online
OpenStudy (anonymous):

Why does Intensity drop off with (1/r^2) but amplitude drop off with only (1/r)?

OpenStudy (anonymous):

intensity isnt like power? the amplitude is proportional to V but power is proportiona to V²

OpenStudy (anonymous):

Intensity is usually defined as the square of amplitude

OpenStudy (anonymous):

It is usually defined as the square of the amplitude yes, but that tells us that it is also proportional to 1/r^2. The one 1/r^2 comes from the fact that the Area of a sphere is 4pir^2, but i can't see how the amplitude is only 1/r.

OpenStudy (anonymous):

If you're fine with intensity having an inverse-square dependence you can just work from that: \[Intensity \propto \frac{1}{r^2}\] \[\sqrt{Intensity} \propto\sqrt{\frac{1}{r^2}}\] \[\therefore Amplitude \propto\frac{1}{r}\]

OpenStudy (anonymous):

That's a neat way of looking at it, thank you!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!