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When monitoring the concentration of a protein by spectrophotometry an absorbance value of 0,6 was measured for 2ml of a 0,8mM aqueous solutio of the protein. After dilution with water, an absorbance of 0,3 was measured. What is the new concentration of the protein solution?
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I was thinking it's similar to what we did, but what dose absorbance mean?
you're using the beer-lambert law, \(Abs=\epsilon*C*l\); which states that \(absorbance\) is \(\propto\) to \(concentration\). Assuming \(\epsilon\) and path-length, \(l\), didn't change. \(\dfrac{Abs_2}{C_2}=\dfrac{Abs_1}{C_1}\)
awww, thank you a lot!
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