Question

nothing

Answer 1

There are a couple of fundamental results which you are being asked to apply here.
Consider:
\[2^3*2^2 = 8*4 = 32 = 2^5\]
and:
\[(2^3)^2 = 8^2 = 64 = 2^6\]
This suggests, perhaps, that:
\[b^n*b^m=b^{n+m}\]
and that:
\[(b^n)^m=b^{nm}\]
This is in fact the case, and the answers follow from these results.

Answer 2

It appears that you need to examine all four submissions and show why they are correct or incorrect. The information provided by @indivicivet will be valuable in proving what is correct or incorrect. To provide a tip, Kelley and Kim are correct, and Mike and Scott are wrong. You now only is to show why.

Answer 3

Do you want me to walk through one of the submissions?

Answer 4

If so which one?

Answer 5

Here are some additional tips\[x ^{1/2}=\sqrt{x}\]

Answer 6

Mike's looks right to me, @radar

Answer 7

\[x ^{2/3}=\sqrt[3]{x ^{2}}\]

Answer 8

I will look at Mike I though he came up with\[x ^{7/5}\]

Answer 9

O.K. Lets look at Mike I already see where i copied it incorrectly, He may be right.\[x ^{8/5}\times x ^{4/5}\over x ^{2/5}\]\[x ^{12/5}\over x ^{2/5}\]\[x ^{10/5}\]\[x ^{2}\]

Answer 10

Mike was right! Sorry Mike:)

Answer 11

Now to write complete sentences for each step.
For the first step. Multiplication you add the exponents if they are to a common base. In this case "x"

For division subtract the exponents when dealing with a common base.

The last step is just simplifying the improper fractional exponent (10/5)=2

Answer 12

Thanks @Indivicivet for pointing out that Mike got it right.

Answer 13

Do you want to do Kelley?

Answer 14

\[\sqrt[7]{x ^{14}}\]is the same as saying\[x ^{14/7}\]the exponent reducing to '2' giving you \[x ^{2}\]which is correct.

Answer 15

Good luck with your studies.

Answer 16

I will sign off if you need no further help on this.

Answer 17

Oh let me check your results.

Answer 18

Yes, Great