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Mathematics 9 Online
OpenStudy (anonymous):

Help!!! Medal!!!

OpenStudy (anonymous):

OpenStudy (studygurl14):

\[P(x) = 55,000\sqrt{x - 1945}\] Plus in years between 1945 and 2000 as x, then solve. Whatever year (or value of x) makes the equation equal 165,000 is the answer.

OpenStudy (studygurl14):

Plug in, not plus in btw

hartnn (hartnn):

or, you could do this, P = 165000 \(165000 = 55 000 \sqrt {x-1945}\) and solve for x

OpenStudy (studygurl14):

true! I didn't think of that! Good job @hartnn !

OpenStudy (studygurl14):

@hartnn 's way is much easier. lol

OpenStudy (anonymous):

ok thanks

hartnn (hartnn):

if you want us to verify your answer, tell us what u get :) and welcome ^_^

OpenStudy (anonymous):

ok I will when I figure up the answer

OpenStudy (anonymous):

would it 1954

OpenStudy (studygurl14):

Yes! Great job!

OpenStudy (anonymous):

Awesome. Thank you guys so much!

OpenStudy (studygurl14):

anytime. :)

hartnn (hartnn):

\(\huge \color{red}{\checkmark}\)

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