Question

one more ..! evaluate the integral ...!

Answer 1

\[ x^2+1 \neq n \Pi , n \in N\]

Answer 2

\[\int\limits x \sqrt{\frac{ 2\sin(x^2+1)-\sin2(x^2+1) }{ 2\sin(x^2+1)+\sin2(x^2+1) }}dx\]

Answer 3

first instinct is to substitute x^2 +1 = u
then use the fact that sin 2t = 2 sint cos t

Answer 4

i reached till here >>\[\int\limits xtan \frac{ x^2+1 }{ 2}dx\]

Answer 5

if you use what "hartnn" says
it will be easy
then note that 1-cosu = 2sin^2 (u/2)
1+cosu = 2cos^2 (u/2)

Answer 6

then put (x^2+1)/2 = u

Answer 7

x dx = du
integral tan u du

Answer 8

thank you all ...thank uuu ..yeahh ..i got it ..!!!

Answer 9

this was a easy one eh ?

Answer 10

yup :)