Question

A chemist needs to mix a 12% acid solution with a 32% acid solution to obtain an 8-liters mixture consisting of 20% acid. How many liters of each of the acid solutions must be used?

Answer 1

x + y = 8
0.12x + 0.32 y = 8(0.20)

Answer 2

Can you solve the system?

Answer 3

can you tell me what I need to do first?

Answer 4

y = 8-x

0.12x+ 0.32(8-x) = 1.6

Answer 5

I solved the simple equation to y = 8-x and then substituted into the 2nd equation

Answer 6

After you simplify, that will tell you how much of the 12% solution you need. You'll have to then solve for the 32% solution by subtracting from 8

Answer 7

so, 4.8 for the 12%?

Answer 8

yes

Answer 9

and then what do I do?

Answer 10

u need the 32% solution amount so 8 - 4.8 = ???

Answer 11

3.2

Answer 12

yes...be sure to label your answers