find the product. simplify if possible 5 over 14 times 4a over 25 A. a over 35 B. 2 over 35 C. 2a over 35 D. a over 30
\(\bf \cfrac{5}{14}\times \cfrac{41}{25}\implies \cfrac{5\times 4a}{14\times 25}\)
so is that C @jdoe0001 ?
well. you said you got C, so, is it?
idk, that was for a different question
hm ok... well.. so.. multiply as then simplify
i don't know how :/
well... what would you get, without simplifying just multiplying, for \(\bf \cfrac{5\times 4a}{14\times 25}\quad ?\)
20 over 350
so \(\bf \cfrac{5}{14}\times \cfrac{41}{25}\implies \cfrac{5\times 4a}{14\times 25}\implies \cfrac{20a}{350}\qquad then\) |dw:1389041508825:dw| \(\bf \cfrac{20a}{350}\implies \cfrac{\cancel{2}\cdot 2\cdot \cancel{5}a}{\cancel{2}\cdot \cancel{5}\cdot 5\cdot 7}\)
ok, so A or D?
\(\bf \cfrac{\cancel{2}\cdot 2\cdot \cancel{5}a}{\cancel{2}\cdot \cancel{5}\cdot 5\cdot 7} \implies ?\)
what's left?
A/35
it is A
notice, we only could cancel out 1 of the "2" above
right
\(\bf \cfrac{\cancel{2}\cdot 2\cdot \cancel{5}a}{\cancel{2}\cdot \cancel{5}\cdot 5\cdot 7} \implies \cfrac{2a}{35}\)
so it was C!!!!
yes, but the idea is to multiply and then simplify, like so
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