Question

Please help me find the sum.

Answer 1

\[\frac{ 2a }{ a ^{2}+4a+4 }+\frac{ 4 }{ a ^{2}+7a+10 }\]

Answer 2

@agent0smith @mustafa2014 @musa19965 @myininaya

Answer 3

@Yukisama201 @YukiArashix @arabpride @DSS

Answer 4

2a/(a+2)(a+2) + 4/((a+5)(a+2)

Answer 5

The common denominator is (a+2)(a+2)(a+5)

2a(a+5) + 4(a+2) / common denominator

2a^2 + 10a + 4a + 8 =(2a^2 + 14a + 8)/(a+2)(a+2)(a+5)

Answer 6

its hard to understand can you please use the equation edit

Answer 7

\[(2a ^{2}+14a+8)/(a+2)(a+2)(a+5)\]

Answer 8

I think that's as simple as you can go.

Answer 9

thank you