Use the Remainder Theorem to find the remainder when P(x) = x^4 – 9x^3 – 5x^2 – 3x + 4 is divided by x + 3.
Take the coefficients = 1, -9, -5 , -3 4 the the solution to x=3=0 which is -3 now -3 | 1 -9 -5 -3 4 -3 36 -93 288 ___________________________ 1 -12 31 -96 292 x`3 -12x`2 +31x -96 _____________________________ x+3 | x`4 - 9x`3 - 5x`2 - 3x + 4 -(x`4 + 3x`3) ______________ -12x`3 -5x`2 -(-12`3 - 36x`2) _________________- 31x`2 -3x -(31x`2 +93x) ______________ -96x +4 -(-96x -288) _____________ 292
Omg, I understand. Thank you so much! :)
np!!!
Question, what is this " ' " by the numbers?
@Jenna_Da_Nerd
hmm, not really sure how to explain that. That's just what i learned o.o
Oh, ok lol, are they very important?
I don't think so
The faster way to do this is to plug in x=-3.
@OtonoGold that's what the remainder theorem is - tells you that the remainder of P(x) when it's divided by x+3 is the result of P(-3) So plug x=-3 into P(x) = x^4 – 9x^3 – 5x^2 – 3x + 4 (but synthetic division is pretty quick I guess anyway)
-3^4-9*-3^3-5*3^2-3*-3+4?
the solve it ? @agent0smith
Yeah but you need brackets everywhere there is an x, so you don't miss any negatives. It's also much faster to use a calculator. \[\Large P(-3) = (-3)^4 – 9(-3)^3 – 5(-3)^2 – 3(-3) + 4\]
Oh okay. Thank you :)
No prob :) but you can do synthetic division if you prefer, the remainder theorem is I guess more defined that way.
The way she did?
@agent0smith
Yes that is synthetic division.
now -3 | 1 -9 -5 -3 4 -3 36 -93 288 ___________________________ 1 -12 31 -96 292 That ^^^
lel #connexuscheatingclub :3 precious
hell yeah ^^^ lolol
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