Consider the line that passes through the point (3, -2) and has a slope of 2. Part 1: Write the equation of this line using point-slope form. (2 points) Part 2: Using your equation from part 1, rewrite this equation in slope-intercept form. Make sure to show all of your work. (2 points) Part 3: Using your equation from part 2, rewrite this equation in standard form. Make sure to show all of your work. (2 points)
Please show steps with how to get the answer
\[y-y_1 = m(x-x_1)\] point-slope form \[y = mx+b ---> slope-intercept form \] \[ax+by = c ----> standard form \]
the m is the slope, and to find the slope, you need the slope formula of \[\frac{ y_2-y_1 }{ x_2-x_1 }\]
after you find the slope, the rest is plugging the points
Please show me how to plug it in for this problem to understand better
i take that back, the slope is already given, so you just need to plug it in
What do the answers come out to?
for the point slope form \[\huge y+2=2(x-3)\]
now you have y+2 = 2(x-3) solve for y, and you would have it in slope intercept form which is y= mx+b
I will write a review for your help and gave a medal . I have been having so much trouble with inequalities. I am a very great student and strive my best but I have trouble
Please give how to get standard form once I plug it in?
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