Question

If a fox starts from rest and accelerates at a rate of 1.1 m/s2, how long does it take the fox to run 5 m?

Answer 1

You need to use a linear formula
We have u,v,a,t,s
u = 0
a = 1.1
s = 5
we want to find t

The formula we need is s=ut+0.5at^2
5 = 0 + 0.5*1.1*t^2
5 = 0.55 t^2
t = sqrt(5/0.55)
t = 9.09 seconds

Therefore it will take 9.09 seconds

Answer 2

it took 3.0s

Answer 3

Sorry, forgot to take the square root. 3 seconds it is. :P

Answer 4

A runner starts from rest and has an acceleration of 3 m/s2. How fast is she running after 1.1 seconds?

Answer 5

@Riddellikins

Answer 6

3*1.1 = 3.3m/s

Answer 7

A truck is moving 14 m/s to the south. If it takes the truck 20 seconds to reduce its velocity to 10 m/s south, what is its acceleration?

Answer 8

4/20 = 0.2m/s/s

Answer 9

north or south?

Answer 10

north

Answer 11

A car crash causes an acceleration of 6.2 g. What is the car's acceleration in meters per second squared?

Answer 12

6.2*9.81=60.822

Answer 13

A runner starts from rest and speeds up with constant acceleration. If she has gone a distance of 30 m at the point when she reaches a speed of 8 m/s, what is her acceleration?

Answer 14

u = 0
v = 8
a = ?
s = 30

What formula do you need?

Answer 15

acceleraton solving for velocity

Answer 16

But what is the actual formula?

Answer 17

doesnt say choices are:
1.1 m/s 2
3.8 m/s 2
9.1 m/s 2
7.5 m/s 2

Answer 18

Yeah, you have to know the formula yourself.
There are four of them (for linear motion under a constant acceleration)

v = u +at
v^2 = u^2 + 2as
s = ut + 0.5at^2
s = 0.5(u+v)t

Answer 19

a= Change in velocity / change in time

Answer 20

No, it's one of the ones that I typed out. Have you learnt them?

Answer 21

no but it was 1.1

Answer 22

A cheetah accelerates from rest at a rate of 5.4 m/s2. How far has the cheetah gone after 1.8 seconds