level curve of function f(x,y,z)=x+y+z..someone please help me!!!
I think the first step is to identify the surface given by f(x,y,z) ..
is it plane??
I'm not quite sure, I just started calculus 3 myself..
@dan815 ?
You get the level curves by setting f(x,y,z) equal to different constant values. So take f(x,y,z)=0 for example, then we have \[x+y+z=0\] This is as you guessed the equation for a plane going through the origin with normal \(\hat{x}+\hat{y}+\hat{z}\). Different constants will only shift this plane upwards or downwards.
Oh, and since we are in 3 dimensions the level sets are called level surfaces.
planes
ask more questions i miss calc 3
Find the equation of the tangent plane to the hyperboloid f(x,y,z)=x^2/a^2 +y^2/b^2 -z^2/c^2 =1 at (x_0,y_0,z_0 )
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