Question

The area of a particular rectangle is 12 times the area of a certain square, and the width of the rectangle is three times the length of a side of the square. The perimeter of the rectangle is 30 units greater than the perimeter of the square. Find the dimensions of both the rectangle and the square.

Answer 1

Area of rectangle=wL. Square=s^s

Answer 2

So

wL=12s^2

w=3s

2w+2L=30+4s

Answer 3

Okay I'm getting it.

Answer 4

Ok, substitute the second equation into the first. And u should het something for L in terms of s

Answer 5

gotcha

Answer 6

So what did u get?

Answer 7

12s^2/3s

Answer 8

And u can simplify that to 4s

Answer 9

right.

Answer 10

wait....It simplifies to 4s^3.....

Answer 11

So u have w=3s and L=4s

Substitute those values for w and L into the last equation and u should be able to find s, which is one side of the square, which is also all 4 sides

Answer 12

No, it just 4s

Answer 13

Were u able to find ur answers?

Answer 14

okay. Yeah thanks

Answer 15

Ok. No problem.
But just checking.

Square=3x3
Rectangle =9x12

Answer 16

YUP! Thanks