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When is a(b+c) = ab+c false? Can I please get an example?
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a=3, b=2, c=1
So what could make it true?
a=1, b=2, c=3
Oh, I see. Thanks! @kc_kennylau
no problem :)
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When you expand a(b+c), you need to multiply both terms inside by a. So to make it true, you need a(b+c) = ab + ac
Thank you very much for the explanation @jollyjolly0
when you're not distributing a all the way
a=0, b=0, c=0 is another true case.
If a=1, it's always true that a(b+c) = ab+c
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\[\begin{array}{rcl} a(b+c)&=&ab+c\\ ab+ac&=&ab+c\\ ac&=&c\\ c=0&\mbox{or}&a=1 \end{array}\]
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