find the integral from x to x^2 (1/t)*ln((1-t)/32)dt
find the\[\int\limits\limits_{x}^{x ^{2}} [1/t]*\ln [(1-t)/32]\]
d/dx of ln(1-t)=-1/(1-t) and not -1/t
So true. Sorry, thinking
hey i by the way i have to differentiate that whole thing
\[d/dx(\int\limits_{x}^{x^2}[1/t]*[\ln ((1-t)/32)])\]
could you help now
That is easier, as they cancel out. We just have to be a bit careful.
but the limit is from x to x^2 what about that where will the limits go
Fundamental Theorem of Calculus, I call you to help my battle http://www.youtube.com/watch?v=PGmVvIglZx8
i know that integral and differential will get canceled but what will t change to will it be x or x^2 or x-x^2 or something else thats what i want to know
thamks for that link
I am just watching that link, it has been fairly long time since I did problems like this.
OK this video was really handy. I hope you can do it now. That dude explained it really clearly.
yup thanks
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