Question

Can someone check my answer?

Answer 1

Suppose the total number of earthquakes with a magnitude of 4 or higher averages 14,500 per year. Approximately how many are magnitude 5 or higher? Show your work.

Answer 2

Answer/work:

4 or higher = 90%
5 or higher = 10%

90% = 14,500
10% = ?

14,500 ÷ 10 = 1,450

90% = 14,500
10% = 1,450

Answer 3

Yeah I think that right

Answer 4

Awesome! Thank you!

Answer 5

Wait! I DID SOMETHING WRONG!!! I forgot to look at this part!

A = earthquakes with a magnitude of 4 to 4.9
B = earthquakes with a magnitude of 5 to 5.9
C = earthquakes with a magnitude of 6 or higher




And if the question said, "Suppose the total number of earthquakes with a magnitude of 4 OR HIGHER averages 14,500 per year." So that would make the whole 100% right?

Answer 6

Would I still have the same answer?