Use the rectangles in each graph to approximate the area of the region bounded by y=sin(x), y=0, x=0, x=pi
without the graph Im afraid we cannot help
im trying to get the graphs
how is that?
Number one. Lets do this
So you can see the scale. From 0 to 1 there are 5 equidistant markers. Thus 1/5=0.2 for each scale.
on the y axis?
That is on the y axis. On the x axis, first image there is pi/4 scales.
ok
The first triangle goes up to 3.5 scale=3.5*.0.2=0.7 and it goes to the right by pi/4. So the area is pi/4 * 0.7
What would be the second rectangles area? ( sorry I put triangle before by accident)
why did you multiply 3.5 by 0.2?
Because the first rectangles goes up to 3.5 scales. Thus one side is 3.5*0.2 long
oh ok
The other side has length pi/4. The area =0.7 *pi/4 (1st rectangle)
so the second rectangle is 1*pi/4=pi/4?
Correct
and the first is 0.7pi/4
And the third is equal to the first. So if you add them up you will get the answer. What is different in the second picture?
there are 5 rectangles
Yes, because the scale on the x axis is different. What is it?
pi/6
Correct again. I think now you have every tool to finish this question
also i think the area for the first graph is 3.4pi/4
im not sure if thats write
oops right*
0.7 *pi/4 +1*pi/4+0.7*pi/4=(0.7+1+.0.7)*pi/4=2.4*pi/4
oh i see where i went wrong
Probably it is neater to present this solution like this: \[0.6\pi \]
thank you so much
For your interest the exact solution, so the area under this graph from 0 to pi is equal to 1.
Oh sorry that was half of it :) It is equal to 2.
it is?
We got 0.6pi=1.885 So it is fairly good approximation. If you do the 2nd picture, the result should be closer to 2.
Yes it is, that area =2
yes it is :)
It is a better approximation. If you split the area into 1000000000000 rectangles than the answer might be 1.999999999
This is where Newton and Leibniz invented Calculus. If you split the graph into infinite many rectangles than the area will be 2!
well you learn something new everyday
:)
Join our real-time social learning platform and learn together with your friends!