Question

precal question

Answer 1

hint:

sin^2 x + cos^2 x = 1

Answer 2

im still dont understand lol @rizwan_uet

Answer 3

in question 3

the numerator is sin^2 x + cos^2 x

as sin^2 x + cos^2 x = 1

now put that value in the fraction you have

Answer 4

put 1 instead of sin^2 x + cos^2 x

Answer 5

1/ cos x like that?

Answer 6

now tell me what sec x = ???

Answer 7

as
sec x = 1/ cos x
=> cos x = 1/sec x --> now guess your answer

Answer 8

d?? @rizwan_uet

Answer 9

\[\huge\color{blue}{ \frac{Sin^2x+Cos^2x}{Cosx} =Secx } \]
we know that \[\huge\color{red}{ Sin^2x+Cos^2x=1 }\]
So the nominator is equal to 1.

REWRITE the question.
\[\huge\color{blue}{ \frac{\color{red} { 1 } }{Cosx} =Secx } \]

Answer 10

Now, we also know that \[\huge\color{blue}{ \frac{1}{Cos~x} =Sec~x } \]
because Sec x and Cos x, (no matter what the x is) are multiplicative inverses of each other.

Answer 11

so it's A then @SolomonZelman