Simplify:
\[2 \sqrt[4]{10}\]
@DSS @Sheraz12345
Clearly No idea.. :/ Sorry
10^(1/4)=1.78 2(10^(1/4)) = 3.56 Other than that, I think it's in the simplest form
Thats what i thought but thats not simplification @DSS
The answer choices are: \[4 \sqrt[4]{5}\] \[8 \sqrt[4]{5}\] \[16 \sqrt[4]{5}\] \[32 \sqrt[4]{5}\]
Oh sorry, the question asks to simplify \[2 \sqrt[4]{80}\]
I was looking at another question :P
\[\Large 2 \sqrt[4]{10} = 2 \sqrt[4]{10}\] that's it. You can't simplify the 4th root of 10.
Use prime factorization on 80. Look for numbers which you can put with an exponent of 4, since you're finding the 4th root. \[\Large 80 = 2*2*2*2*2*5=2^4 *2*5\] \[\Large 2 \sqrt[4]{2^4*2*5}= 2 \sqrt[4]{2^4}* \sqrt[4]{2*5}\]Try simplifying.
I don't understand ._. Could you explain how I get the answer, I don't understand what you wrote. @DSS Could you help?
Do you understand prime factorization?
Circles are the prime factors |dw:1389124311454:dw| 80 = 2*2*2*2*2*5
I know how to factorize, I just don't know how to get the simplified form from that.
Well then tell me where you got lost. This is still the original problem, we just factored 80 \[\Large 2 \sqrt[4]{2^4*2*5}= \]
Okay, go on..
Break up the 4th root \[\Large 2 \sqrt[4]{2^4*2*5}= 2 \sqrt[4]{2^4}* \sqrt[4]{2*5}\]
Gotcha so far..
What's the 4th root of 2^4? hint: the nth root of x^n is x.\[\huge \sqrt[n]{x^n} = x\]
We can't do anything with the 2*5 so leave that as 10.\[\Large 2 \sqrt[4]{2^4}* \sqrt[4]{10}\]
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