Question

Help! Halfway there. Two square pyramids have the same volume. For the first pyramid, the side length of the base is 16 in and the height is 28. On the 2nd pyramid the height is 112. What is the side length of the base of the 2nd pyramid?

Answer 1

V=1/3(S^2)(h)
V=(1/3)(16^2)(28)
V=2389

2389=(1/3)(112)(S^2) ??? this is where im starting to get confused.

Answer 2

@Compassionate would you know how to do this?

Answer 3

My account keeps signing me out! really irritating!

Answer 4

Hey ive gotten signed out too! It happened only once though.

Answer 5

It's happened like five times to me. I'm going to write it up in notepad. Okay? Might take awhile because of my connection! Grr

Answer 6

Still need help @Ashleyisakitty ?

Answer 7

Okay, that sounds good. And yes Studygurl.

Answer 8

okay. so hold on a sec while I type it up

Answer 9

@Ashleyisakitty its basically what i just showed you.

Answer 10

guys let me have this one?

Answer 11

so you have 2 equations. 1 to find the volume of both. use the first triangle.

Answer 12

\[V=1/316^{2}*28\] thats for your volume

Answer 13

so it comes out to 2389.33

Answer 14

Yes.

Answer 15

Use that as your Volume for the second equation.

Answer 16

Soooo it would look like this \[2389.33=1/3x ^{2}*112\]

Answer 17

Yes, so you solve for S:

112/3 = 37.33, so:

2390 = 37.33*(S^2)

64.02 = S^2

S = 8 in

Answer 18

so 7.9

Answer 19

Well did it say to round?

Answer 20

Great. awesome. Thank you everyone. Medals for everyone!

Answer 21

Yes im going to round up.

Answer 22

Oh ok welcome . ^-^

Answer 23

Sorry I was late. It kept signing me out.

Answer 24

No worries! Thanks for the effort :)

Answer 25

@Compassionate i gave you a medal for helping too

Answer 26

#sweg

Answer 27

sorry I left @Ashleyisakitty . I had to eat lunch, then I had computer troubles. sorry!