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Mathematics 10 Online
OpenStudy (anonymous):

What is the length of AA' ?

OpenStudy (anonymous):

OpenStudy (isaiah.feynman):

A and A' are just the vertices of the two squares.

OpenStudy (anonymous):

Okay, that doesn't answer the question or even tell me how to solve it...

OpenStudy (isaiah.feynman):

Do they mean the distance between A and A'?

OpenStudy (anonymous):

I have no idea. :/ I've never seen this before and my lesson doesn't show me how.

OpenStudy (anonymous):

OpenStudy (anonymous):

Yeah, you can specify a line with two points. The length AA' would mean the same as the distance between A and A'. To go from A to A' you go 5 units across and 2 up. Do you know Pythagoras's theorem? That will get you the answer.

OpenStudy (anonymous):

\[a ^{2}+b ^{2}=c ^{2}\]?

OpenStudy (anonymous):

That's it. a and b are 5 and 2, so c is the answer

OpenStudy (anonymous):

7?

OpenStudy (anonymous):

that doesnt match with my answer box

OpenStudy (agent0smith):

\[\Large 5^{2}+2 ^{2}=c ^{2}\]first, what is 5^2 + 2^2?

OpenStudy (anonymous):

25 + 4 ?

OpenStudy (agent0smith):

so\[\Large c^2 = 29\]so c squared is 29. Find c.

OpenStudy (anonymous):

5.38?

OpenStudy (agent0smith):

idk if you're supposed to leave it as exact or a decimal. Exact would be square root of 29.

OpenStudy (anonymous):

wait, wouldn't my answer just be \[\sqrt{29}\]

OpenStudy (isaiah.feynman):

Yes.

OpenStudy (anonymous):

Ahh, well that was easy once I understood it, thanks!

OpenStudy (isaiah.feynman):

You can also use the distance formula too to do it..you'd still get sqrt 29.

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