Simplify the expression: 14/(3x) + (x+5)/(3x)
\[ \frac{14}{3x} + \frac{(x+5)}{3x}\] So what can you tell about the two terms' denominators?
And also remember that, similarly, \[\frac{1}{2} + \frac{1}{2} = \frac{(1+1)}{2} = \frac{2}{2}=1\]
so 1 is the answer? really
No no no, sorry. That as just an example of two two with the same denominator. It has nothing to do calculation wise with the problem at hand.
~Two terms
so what is the answer?
Have a go at it first. Just like in the example, they both have the same denominator (bottom term) - in your problem, it's 3x; so you add the numerators and put the sum over their common denominator.
i really cant this isn't my homework its my other friends i told her i would see if could get the answer idk how do this haven't learned it yet shes older
Well, \[14 + x + 5=?\]
You can think of it as \[ x + (14+5) = x + \ ?\]
What would the question mark be?
(promise it'll take two seconds after this, and you can show your friend and impress them! Much better than just an answer.)
ok thank you :)
3?
Following through, the question mark would be 14+5 \[14+x+5 = x + (14+5) = x+19\] This is the sum of the numerator \[\frac{\overset{\text{this top term}}{14}}{3x}+\frac{\overset{\text{and this top term}}{(x+5)}}{3x}\] So then the answer would be that sum above (x+19) all divided by the denominator (3x) \[\frac{14}{3x} + \frac{(x+5)}{3x} = \frac{14+x+5}{3x}\] Follow?
not really im only in 7th i have no idea what your doing she is in the 12 grade lol
No worries ^_^ It's exactly like adding fractions, except with a few letters thrown in. ^_^ in any case, the answer your friend is looking or is \[\frac{x+19}{3x}\]
thank you mamn
Very welcome - happy start of the semester!
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