Graph the relation {(5, 0), (0, 5), (5, 1), (1, 5)}. Is it a function? Why or why not?
A. Yes, it passes the horizontal-line test B. Yes, it passes the vertical-line test. C. No, it does not pass the vertical-line test.. D. No, it does not pass the horizontal-line test these are my choices
\(\bf {(5, 0), (0, 5), (5, 1), (1, 5)}\implies \begin{array}{llll} x&\bf y\\ \hline\\ 5&0\\ 0&5\\ 5&1\\ 1&5 \end{array}\) recall, to pass the vertical line test, or be a function each "y" must have a unique "x" in the set
so... what do you think?
so it would be answer B???/
if you give me the answer ill give you a medal
I don't think that's the idea behind the exercise
what do you mean?/
look at the "y" set do all of them have a different "x" ?
all i need is the answer
yes they do
so.... you don't have any "x" repeats?
i have one don't i?
\(\bf {(5, 0), (0, 5), (5, 1), (1, 5)}\implies \begin{array}{llll} x&\bf y\\ \hline\\ \color{red}{5}&0\\ 0&5\\ \color{red}{5}&1\\ 1&5 \end{array}\)
yea see only one
ahh, then is NOT a function in a function, there cannot be any "x" repeats
so my answer would be C?
yeap
thank you sir
yw
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