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Mathematics 7 Online
OpenStudy (anonymous):

Graph the relation {(5, 0), (0, 5), (5, 1), (1, 5)}. Is it a function? Why or why not?

OpenStudy (anonymous):

A. Yes, it passes the horizontal-line test B. Yes, it passes the vertical-line test. C. No, it does not pass the vertical-line test.. D. No, it does not pass the horizontal-line test these are my choices

OpenStudy (jdoe0001):

\(\bf {(5, 0), (0, 5), (5, 1), (1, 5)}\implies \begin{array}{llll} x&\bf y\\ \hline\\ 5&0\\ 0&5\\ 5&1\\ 1&5 \end{array}\) recall, to pass the vertical line test, or be a function each "y" must have a unique "x" in the set

OpenStudy (jdoe0001):

so... what do you think?

OpenStudy (anonymous):

so it would be answer B???/

OpenStudy (anonymous):

if you give me the answer ill give you a medal

OpenStudy (jdoe0001):

I don't think that's the idea behind the exercise

OpenStudy (anonymous):

what do you mean?/

OpenStudy (jdoe0001):

look at the "y" set do all of them have a different "x" ?

OpenStudy (anonymous):

all i need is the answer

OpenStudy (anonymous):

yes they do

OpenStudy (jdoe0001):

so.... you don't have any "x" repeats?

OpenStudy (anonymous):

i have one don't i?

OpenStudy (jdoe0001):

\(\bf {(5, 0), (0, 5), (5, 1), (1, 5)}\implies \begin{array}{llll} x&\bf y\\ \hline\\ \color{red}{5}&0\\ 0&5\\ \color{red}{5}&1\\ 1&5 \end{array}\)

OpenStudy (anonymous):

yea see only one

OpenStudy (jdoe0001):

ahh, then is NOT a function in a function, there cannot be any "x" repeats

OpenStudy (anonymous):

so my answer would be C?

OpenStudy (jdoe0001):

yeap

OpenStudy (anonymous):

thank you sir

OpenStudy (jdoe0001):

yw

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