Question

@whpalmer4 can you help me with 3 math questions please

Answer 1

I only need help with 2 i already did 1

Answer 2

@Luigi0210 u there?

Answer 3

@wolf1728 can you help me please with 2 questions?

Answer 4

@jim_thompson5910 can u help me?

Answer 5

If you had something like this function \[\Large f(x) = \frac{1}{x-1}\]

then the function is undefined at x = 1 because this value makes the denominator x-1 equal to zero

remember you CANNOT divide by zero

Answer 6

let me know if that example helps or not

Answer 7

it helps can u work it out for me

Answer 8

give it a shot and tell me what you get

Answer 9

okay

Answer 10

idk :( can you work the problem out for i dont understand it

Answer 11

if I told you that the function wasn't defined at x = 2, what would that mean?

Answer 12

what would the denominator look like?

Answer 13

x-2?

Answer 14

good

Answer 15

because...

x-2

2 - 2 ...replace x with 2 (since x = 2)

0

but you cannot divide by zero, so x cannot equal 2 (ie x = 2 is undefined)

Answer 16

if x = 5 was undefined then the denominator is???

Answer 17

x-5?

Answer 18

if x = -7 was undefined then the denominator is ________

Answer 19

x+7?

Answer 20

good, you got the hang of it

Answer 21

oh kay so how do i put that into an answer for -2,3 and 5?

Answer 22

if x = -2 is undefined, then x+2 is part of the denominator

Answer 23

oh kay can u put answer the question so i can type it in my own words?

Answer 24

if x = 3 is undefined, then x-3 is part of the denominator

Answer 25

put all of these factors to get (x+2)(x-3)(x-5)

if the denominator is (x+2)(x-3)(x-5), then x = -2, x = 3, x = 5 are all undefined

Answer 26

notice how if you plugged in x = 3 into (x+2)(x-3)(x-5), you would eventually end up with 0 as a result in the denominator

so that shows us that x = 3 is undefined for this function

Answer 27

okay so I have to describe in which situation either bobby or charles is correct or if both are correct

Answer 28

well I have described one of those

which one did I describe?

Answer 29

charles?

Answer 30

so x = -2 is defined for the function

\[\Large f(x) = \frac{1}{(x+2)(x-3)(x-5)}\]
???

Answer 31

so are they both correct then?

Answer 32

plug x = -2 into that function and evaluate

Answer 33

okay

Answer 34

I have another question which i kinda get but im kinda stuck can u help me?

Answer 35

what's that?

Answer 36

how far did you get?

Answer 37

okay i know taht it has to be set up like this