Tim walked one fifth of a mile on Monday, six sevenths of a mile on Tuesday, and two over three of a mile on Wednesday. How far did he walk in all?

Question

jdoe0001 · Answer

$\large \begin{array}{cccccclllllll}
\cfrac{1}{5}&+&\cfrac{6}{7}&+&\cfrac{2}{3}&=\cfrac{}{lcd?}\ \quad \
monday&&tuesday&&wednesday
\end{array}$

anonymous · Answer

im giving out medals

jdoe0001 · Answer

so.... what would be our lcd?

jdoe0001 · Answer

lcd = a number we can divide, by 7, 5,and 3

anonymous · Answer

uhm 1?

jdoe0001 · Answer

$1 \div 5 ? $    doesn't look very divisible

anonymous · Answer

I guess that's true

jdoe0001 · Answer

35 is divisible by 7 and 5
$\bf 35\div 7 = 5\qquad 35\div 5=7$   but is not divisible by 3.... so no dice on that one, has to be something else

jdoe0001 · Answer

any ideas?

anonymous · Answer

About one and one half  is another idea but just about the same as one then theres 2 is what I am seeing

jdoe0001 · Answer

anyhow, if we just multiply 5 * 7 * 3
whatever number we get, will be divisible by all 3 :)
since it came out of their multiplication anyway

jdoe0001 · Answer

so that's your lcd

and since you know how to add fractions, then use the lcd  and then simplify :)