if the lengths of the segments are 5 inches and 20 inches, find the length of the altitude
could you try providing a diagram? :)
the problem doesn't provide a diagram
then what topic is this covering? :) triangles? parallelograms?
Ratio, proportion, and similarity
are you sure there isn't a picture of the shape or something that goes alone with it? :/
no its just a problem to solve
then I'm not sure... sorry... perhaps I can call for some help from some others that might know... @jdoe0001 @Loser66 @agent0smith
yes could you please
looks pretty ambiguous
@sharona ,either you have failed to provide us a diagram, or you are missing information. Check the problem again.
a segment it's just a line could be altitude or any part of any polygon really
got picture?
no no picture just applying skills
hehe, clairvoyance skills? =)
I can't help you, and I doubt anyone else can help you with the information you are given. Could you please provide a screenshot of the problem?
well, to get an altitude, you'd need more info than that
the altitude to the hypotenuse of a right triangle divides the hypotenuse into two segments
thats all it says her and then they give me the problem
|dw:1389139789748:dw|
here*
NOW the problem is solvable.
yes this looks right can you please help me solve it
hehehe, so there's a picture you didn't provide =)
|dw:1389139837208:dw| the three triangles are similar by AA similarity. That is, the two inner ones and the big one. Therfore take 5/x=x/20 multiply both sides by x: 5=x^2/20 x^2-100=0 Solve that equation and take the positive solution, which will be your side length.
no there is no picture i just learned this today in class and i am just so confused
ok.... so.... what you're after is the so-called "geometric mean" so following the picture by inkyvoyd it'd be like -> http://www.mathwarehouse.com/geometry/similar/triangles/geometric-mean.php notice in the picture below here running a line likewise from the top right-angle vertex, making right angle at the bottom gives 3 SIMILAR triangles the 2 smaller ones contained and the bigger one containing the smaller 2 so you use their ratio
and solve for "x"
okay thanks a lot
yw
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