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Mathematics 20 Online
OpenStudy (anonymous):

write a recursive and explicit formula for the following sequence; 1,4,10,22

OpenStudy (anonymous):

does anybody know the answer?

OpenStudy (anonymous):

Well, to find the recursive relationship, note that the difference between each term is 3*n (assuming you count the first term as 0)

OpenStudy (anonymous):

I have to go now, but ill take another crack at the explicit formula when I get back.

OpenStudy (anonymous):

my guess for the explicit form would be nth number in sequence = \[1+3\sum_{k=0}^{n}2^{k}\] that sequence doesn't include the first term, it just goes 4,10,22,46,94... etc Sorry if that doesn't help. I genuinely can't come up with anything =(

OpenStudy (anonymous):

thank you though

OpenStudy (anonymous):

how about the recrusive?

OpenStudy (anonymous):

don't really understand how you got that one

OpenStudy (anonymous):

I posted a recursive thing above. Each term is double the previous term + 2

OpenStudy (anonymous):

Basically, I used "the difference between each term is 3*n (assuming you count the first term as 0)" to find that sum equation above. The recursive relationship is that each term is double the previous term + 2

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