Question

y = sec^2(sqrt(x))

Answer 1

and?

Answer 2

\[y = \sec ^{2}\sqrt{x} \]

Answer 3

Find the deriv

Answer 4

\[y=\sec^2(\sqrt{x})\]

Answer 5

\[y'=2\sec(\sqrt{x})\cdot\sec(\sqrt{x})\cdot\tan(\sqrt{x})\cdot\left(\frac{1}{2\sqrt{x}}\right)\]

Answer 6

You can draw it if you'd like. I'll be able to follow whatever it is you're doing

Answer 7

\[=\frac{\tan(\sqrt{x})\cdot\sec^{2}(\sqrt{x})}{\sqrt{x}}=\frac{\sqrt{x}\tan(\sqrt{x})\cdot\sec^{2}(\sqrt{x})}{x}\]

Answer 8

is that what you got?