Express cos(2x) in terms of sin(x).
This involves an trigonometric identity! Which one involves 2x?
This is the double angle for cosine, but I don't know how to experss it in terms of sin(x).
\(\ \large \text{Okay, let's go back... What's the double angle identity for cosine?} \)
1-2sin^2(x) = cos(2x)
\(\ \Large \text{Exactly! That's it! That's in terms of sin(x)!} \)
Oh! Okay :) Thanks. Do you mind helping me with another trig problem?
\(\ \Huge \text {I'll try my best ;)} \)
\(\ \text {By the way -- Welcome to OpenStudy!} \)
Express |dw:1389147878332:dw| and find the sum of a+b+c= ? without using a calculator
that's radical of a+b(radical c)
and thanks :)
Hmmm...I'm not really sure. I'd say start by knowing what cos60 is and working from there?
Oh, alright thanks anyway :)
1-2 sin^2 x
we know that cos 2a =cos^2a-sin^2a =1-sin^2a-sin^2a=1-2sin^2a
i think u got this
Join our real-time social learning platform and learn together with your friends!