Question

Write the equation of the graph in vertex form

Answer 1

here is the graph

Answer 2

@eliassaab

Answer 3

i know the equation to find vertex form is a(x-h)^2+k where (h,k) is the vertex. i also thing the vertex is (0,8) but i am not sure.

Answer 4

sorry the vertex is not (0,8) i was looking at the wrong graph i think it is (-1,-8)

Answer 5

the vertex is at (-1,-8)

Answer 6

ok so i did get that right well how do we find what a is i have no clue what that is

Answer 7

here is the step by step solution

http://www.algebra.com/algebra/college/linear/Linear_Algebra.faq.question.117607.html

Answer 8

ok i have another question can you help

Answer 9

post it

Answer 10

rewrite the equation in vertex form. \[y=x ^{2}+2x+4\]
and when you graph that the vertex in (0,8)

Answer 11

follow the same procedure as above

Answer 12

\[

y= x^2 +2x +1 +3=(x+1)^2 +3\\
y-3 =(x+1)^2
\]

Answer 13

i have gotten this far and am not sure.
\[ax ^{2}+8\] but im not sure if im right

Answer 14

how did you get the long equation

Answer 15

4=3+1

Answer 16

so why did you separate it?

Answer 17

because \( x^2 + 2x +1 =(x+1)^2\) is a perfect square

Answer 18

"eliassaab" say that in standard form ,
but if you know derivation , it is easy to find vertex by f'=0

Answer 19

You do not need derivation for this kind of problem. Completing the square is the method for High School students

Answer 20

ok so how do you do that

Answer 21

See my post above

Answer 22

yes i didnt see it before :) is that the answer to the problem.

Answer 23

\[
y= x^2 +2x +1 +3=(x+1)^2 +3\\
y-3 =(x+1)^2
\]

Answer 24

You can see that the vertex is (3,-1)

Answer 25

i thought it was (0,8) that is what wizwan_uet said

Answer 26

This is the answer for your second problem and it is correct.

Answer 27

For the first one the answer is
\[
y-8=2 (x+1)^2
\]

Answer 28

wait which one are we working on the top problem with the graph?

Answer 29

The one with the graph has as solution\[
y-8=2 (x+1)^2
\]

Answer 30

i still dont get that one but lets finish the problem we are on with the equation.
\[y=x ^{2}+2x+4\]

Answer 31

Both of them, I gave you the answer for. What do you not understand?

Answer 32

That is why you should post each problem separetlely to not get confused

Answer 33

i will do that for now on but for the on with the graph i dont know how you got the original equation. and then go from there please @eliassaab

Answer 34

You can see from the graph that the vertex is (-1,-8)
so the the vertex equation is
\[
y+8 = a( x+1)^2
\]
We have to find a. Since at x=0, y=-7, which gives
-7+8 =a(0+1)^2=a=1
Hence the equation is
\[
y+8 = (x+1)^2
\]
Sorry, I had one misprint in my previous post where I wrote y-8 instead of y+8

Answer 35

Did you get it?