If f(x) = x^2 + 1 and g(x) = 3x + 1, find g(20) + f(6).
\[f(x)=x^2+1~~~~~~~~~and~~~~~~~~~~~g(x)=3x+1\] plug in 6 for x into \[x^2+1\] to find f(6). and plug in 20 for x into \[3x+1\] to find g(20) add the new functions that you come up with, and there will be your answer.
\[f(6)=\color{blue} { 6 } ^2+1~~~~~~~~->~~~~~~~~~f(6)=37\] \[g(20)=3 \times \color{blue} { 20 } +1~~~~~~~~~->~~~~~~~~~g(20)=61\]
98?
\[g(20)+f(6)\] is the same as adding what they are equal to. \[\color{red} { 61+37 } \] so YES, 98 is correct!
So to solve an f(x) equation in that form I just input and then add the solutions?
Also, does that mean f and g have no value?
Yes, f and g have no value. (to say g=...) wouldn't make sense of course)
Got it, Thank you.
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