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Physics 10 Online
OpenStudy (anonymous):

Balance the Equation for the reaction between iron & oxygen. Pleasee explain :3

OpenStudy (anonymous):

| | Fe + | | O2 = | | Fe2O3

OpenStudy (theeric):

Hi! This would be more relevant in the chemistry section... But chemistry is very related to physics. Do you know what the numbers mean?

OpenStudy (anonymous):

Their aren't many people in Chemistry :(

OpenStudy (anonymous):

There*

OpenStudy (theeric):

Fe\(\color{red}{_2}\)O\(\color{red}{_3}\) Those numbers... I know.. I saw this and thought maybe I should head there. But my chemistry doesn't go past the basic level... So I don't go there as much!

OpenStudy (anonymous):

Those numbers mean... Umm, if I remember......... How many bonds each element has?

OpenStudy (theeric):

No, but at least you're thinking chemistry! They are the number of that element that appears in the molecule! So \(\mathrm{Fe_2O_3}\) has 2 Fe (2 iron) and 3 O (3 oxygen).

OpenStudy (anonymous):

Ohhh okay, got it!

OpenStudy (anonymous):

So whats the next step in solving this?

OpenStudy (theeric):

Well, put the pieces of the puzzle together! Well, I guess find how many pieces of each there are. You almost know the end result, \(\mathrm{?\ Fe_2O_3}\). So, you have the \(\mathrm{Fe}\) molecule, which is just one \(\mathrm{Fe}\) atom. And you have the \(\mathrm{O_2}\) element, which is two \(\mathrm{O}\) atoms. Are you comfortable with algebra?

OpenStudy (anonymous):

Lol, algebra is one of the subject that I'm struggling with.

OpenStudy (anonymous):

subjects*

OpenStudy (theeric):

Okay... Algebra makes it easier, but you can try to think about it otherwise. Now, some \(\mathrm{Fe}\) and some \(\mathrm{O_2}\) are going to mix to make some \(\mathrm{Fe_2O_3}\). That's what's going on. You need at least how many \(\mathrm{Fe}\)? You need at least how many \(\mathrm{O}\)?

OpenStudy (theeric):

\(\mathrm{O_2}\), I mean.

OpenStudy (anonymous):

I think I understand... If the end result is Fe2O3, then a 2 belongs in the | | for Fe and a 1 belongs in the | | for O2 ?

OpenStudy (theeric):

But then you'll have \(\mathrm{2Fe+1O_2\rightarrow ?Fe_2O_\color{red}{???}}\) You don't have enough \(\mathrm{0}\)'s for the right side! But we're getting somewhere! What do you think now?

OpenStudy (anonymous):

Hmmm.... Explain to me lol because I'm not sure... If I added that one to the O2, why wouldn't there be enough Oxygen on the right side?

OpenStudy (theeric):

Okay, Well one \(\mathrm{O_2}\) is two \(\mathrm{O}\) atoms. And \(\mathrm{Fe_2O_3}\) has three \(\mathrm{O}\) atoms. See the issue?

OpenStudy (anonymous):

Okay. Yeah I see.

OpenStudy (anonymous):

But adding 2 to the Fe is okay? It was right?

OpenStudy (theeric):

Okay! So let's give another \(\mathrm{O_2}\) to the other side, now. And we'll see about the \(\mathrm{Fe}\). \(\mathrm{2Fe+2O_2\rightarrow ?Fe_2O_\color{red}{???}}\) So...how many \(\mathrm{O}\) atoms do you have on the left side?

OpenStudy (anonymous):

4 O atoms?

OpenStudy (theeric):

Right! So if we have four \(\mathrm{O}\) atoms on the left, we have to have four on the right. If we have \(\mathrm{1Fe_2O_3}\), then we're missing an \(\mathrm{O}\) atom. Soo... Let's try again. But we'll have to make at least one more \(\mathrm{Fe_2O_3}\) (we already have more than enough oxygen, and it hasn't worked out yet). So we'll try three \(\mathrm{O}\) atoms. \(\mathrm{2Fe+3O_2\rightarrow 2Fe_2O_3}?\) How many \(\mathrm{O}\) are on the right?

OpenStudy (theeric):

I mean left!

OpenStudy (anonymous):

Left lol silly me

OpenStudy (anonymous):

5 Oxygen on the left

OpenStudy (theeric):

\(\mathrm{3O_2}\) is like \(\mathrm{O_2+O_2+O_2}\). What do you think now?

OpenStudy (anonymous):

Ohh when there is number to the left of the element -- and it becomes like to the power ^? Or is it just for this scenario? Its 6 Oxygen btw!

OpenStudy (theeric):

When it's to the left, it's how many molecules you have. The subscript one (down below) is is how many of that atom are in the molecule.|dw:1389224426965:dw|

OpenStudy (theeric):

So yep, 6 oxygen. And on the right?

OpenStudy (anonymous):

Ohhh okay! Got it, got it.

OpenStudy (anonymous):

You're asking me how many Oxygen are on the right now?

OpenStudy (theeric):

Yup! In this one: \(\mathrm{2Fe+3O_2\rightarrow 2Fe_2O_3}?\)

OpenStudy (theeric):

(Same one)

OpenStudy (anonymous):

1 oxygen.

OpenStudy (theeric):

Well, you have to look at how many molecules with oxygen you have on the right. Then you have to look at how many oxygen molecules each atom has.

OpenStudy (theeric):

\(\mathrm{2Fe_2O_3}\)

OpenStudy (theeric):

How many molecules? And how many atoms in each?

OpenStudy (anonymous):

How do I know how many oxygen molecules each atom has? Sorry for asking so many questions >.<

OpenStudy (theeric):

Questions are what OpenStudy is for, haha! :)|dw:1389224818705:dw|

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