Balance the Equation for the reaction between iron & oxygen. Pleasee explain :3
| | Fe + | | O2 = | | Fe2O3
Hi! This would be more relevant in the chemistry section... But chemistry is very related to physics. Do you know what the numbers mean?
Their aren't many people in Chemistry :(
There*
Fe\(\color{red}{_2}\)O\(\color{red}{_3}\) Those numbers... I know.. I saw this and thought maybe I should head there. But my chemistry doesn't go past the basic level... So I don't go there as much!
Those numbers mean... Umm, if I remember......... How many bonds each element has?
No, but at least you're thinking chemistry! They are the number of that element that appears in the molecule! So \(\mathrm{Fe_2O_3}\) has 2 Fe (2 iron) and 3 O (3 oxygen).
Ohhh okay, got it!
So whats the next step in solving this?
Well, put the pieces of the puzzle together! Well, I guess find how many pieces of each there are. You almost know the end result, \(\mathrm{?\ Fe_2O_3}\). So, you have the \(\mathrm{Fe}\) molecule, which is just one \(\mathrm{Fe}\) atom. And you have the \(\mathrm{O_2}\) element, which is two \(\mathrm{O}\) atoms. Are you comfortable with algebra?
Lol, algebra is one of the subject that I'm struggling with.
subjects*
Okay... Algebra makes it easier, but you can try to think about it otherwise. Now, some \(\mathrm{Fe}\) and some \(\mathrm{O_2}\) are going to mix to make some \(\mathrm{Fe_2O_3}\). That's what's going on. You need at least how many \(\mathrm{Fe}\)? You need at least how many \(\mathrm{O}\)?
\(\mathrm{O_2}\), I mean.
I think I understand... If the end result is Fe2O3, then a 2 belongs in the | | for Fe and a 1 belongs in the | | for O2 ?
But then you'll have \(\mathrm{2Fe+1O_2\rightarrow ?Fe_2O_\color{red}{???}}\) You don't have enough \(\mathrm{0}\)'s for the right side! But we're getting somewhere! What do you think now?
Hmmm.... Explain to me lol because I'm not sure... If I added that one to the O2, why wouldn't there be enough Oxygen on the right side?
Okay, Well one \(\mathrm{O_2}\) is two \(\mathrm{O}\) atoms. And \(\mathrm{Fe_2O_3}\) has three \(\mathrm{O}\) atoms. See the issue?
Okay. Yeah I see.
But adding 2 to the Fe is okay? It was right?
Okay! So let's give another \(\mathrm{O_2}\) to the other side, now. And we'll see about the \(\mathrm{Fe}\). \(\mathrm{2Fe+2O_2\rightarrow ?Fe_2O_\color{red}{???}}\) So...how many \(\mathrm{O}\) atoms do you have on the left side?
4 O atoms?
Right! So if we have four \(\mathrm{O}\) atoms on the left, we have to have four on the right. If we have \(\mathrm{1Fe_2O_3}\), then we're missing an \(\mathrm{O}\) atom. Soo... Let's try again. But we'll have to make at least one more \(\mathrm{Fe_2O_3}\) (we already have more than enough oxygen, and it hasn't worked out yet). So we'll try three \(\mathrm{O}\) atoms. \(\mathrm{2Fe+3O_2\rightarrow 2Fe_2O_3}?\) How many \(\mathrm{O}\) are on the right?
I mean left!
Left lol silly me
5 Oxygen on the left
\(\mathrm{3O_2}\) is like \(\mathrm{O_2+O_2+O_2}\). What do you think now?
Ohh when there is number to the left of the element -- and it becomes like to the power ^? Or is it just for this scenario? Its 6 Oxygen btw!
When it's to the left, it's how many molecules you have. The subscript one (down below) is is how many of that atom are in the molecule.|dw:1389224426965:dw|
So yep, 6 oxygen. And on the right?
Ohhh okay! Got it, got it.
You're asking me how many Oxygen are on the right now?
Yup! In this one: \(\mathrm{2Fe+3O_2\rightarrow 2Fe_2O_3}?\)
(Same one)
1 oxygen.
Well, you have to look at how many molecules with oxygen you have on the right. Then you have to look at how many oxygen molecules each atom has.
\(\mathrm{2Fe_2O_3}\)
How many molecules? And how many atoms in each?
How do I know how many oxygen molecules each atom has? Sorry for asking so many questions >.<
Questions are what OpenStudy is for, haha! :)|dw:1389224818705:dw|
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