Question

Help? I don't understand this at all...

Answer 1

Determine the amplitude, period, and left and right endpoints for the following.
\[y=\frac{ 1 }{ 2}\sin(x-\frac{ \pi }{ 3}\]

Answer 2

Ugh. It didn't show up. The problem is y=1/2sin(x-(pi/3))

Answer 3

It did show, maybe it hasn't loaded on your end :)

Answer 4

sine functions are in the general form y = Asin(Bx + C) + D
A represents the amplitude
B is the frequency
C is the horizontal translation (phase)
D is the vertical translation

y = Asin(Bx + C) + D
y=1/2sin(x-(pi/3))

We can see that A=0.5, B=1, C=-Pi/3, D=0

From this we can say that the amplitude is 0.5 since A=0.5.

The period of the function is given by 2Pi/B (in any situation)
So:
2Pi/B = 2Pi/1 = 2Pi
Therefore the period is 2Pi.

Not sure what it means by left and right endpoints. The function continues infinitely so I can't see what it would mean. Sorry I can't help you on that part

Answer 5

Oh. Haha. Thanks. :)

Answer 6

@mathstudent55

Answer 7

@Isaiah.Feynman

Answer 8

@Euler271

Answer 9

for the endpoints they most likely mean if you only consider 1 period of it.


we see it is shifted pi/3 to the right so the left endpoint is at pi/3

the right endpoint is at pi/3 + period.

the period is 2pi. [2pi / angular frequency]

so the endpoints are pi/3 and 7pi/3

Answer 10

or maybe the answer is -infinity to +infinity, as it should be, but most likely what i said

Answer 11

Ahh, that would make sense @Euler271