If x varies inversely with y and x = 8 when y = 6, find y when x = 10. A. y = 4.8 B. y = 7.5 C. y = 40/3 D. y = 5/12 B?
@jigglypuff314
The variable y is said to be inversely proportional to x if xy=k for some constant k. This is equivalently stated as "y varies indirectly with x." so plug in the first two x and y values to find k then plug in the second x and k to find the second y
Umm.. confused :/
find k when xy = k (8)(6) = ?
then plug k into xy = k and solve for y (10)y=(k)
48
\(\bf \begin{array}{llll} \textit{something }&\textit{varies inversely to }&\textit{something else}\\ \quad \\ \textit{something }&=\cfrac{(\textit{some value })}{\textit{something else}}\\ \quad \\ y&=\cfrac{(n)}{x} \end{array}\\ \quad \\ x=8\qquad y=6\\ \quad \\ \implies y=\cfrac{(n)}{x}\implies 6=\cfrac{n}{8}\) find "n" first
once you find "n", plug it back in \(\bf y=\cfrac{(n)}{x}\) along with the given "x" value to find "y"
its A?
dunno... what did you get?
correct :)
you know.. I thought that was the answer the first time.. don't know what changed O.o
oh, and thanks :)
glad we could help :)
i gtg ttyl :)
ok, bye!
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