If x varies inversely with y and x = 8 when y = 6, find y when x = 10.
A. y = 4.8
B. y = 7.5
C. y = 40/3
D. y = 5/12
B?
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OpenStudy (lovelyanna):
@jigglypuff314
jigglypuff314 (jigglypuff314):
The variable y is said to be inversely proportional to x if xy=k for some constant k. This is equivalently stated as "y varies indirectly with x."
so plug in the first two x and y values to find k
then plug in the second x and k to find the second y
OpenStudy (lovelyanna):
Umm.. confused :/
jigglypuff314 (jigglypuff314):
find k when xy = k
(8)(6) = ?
jigglypuff314 (jigglypuff314):
then plug k into xy = k
and solve for y (10)y=(k)
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OpenStudy (lovelyanna):
48
OpenStudy (jdoe0001):
\(\bf \begin{array}{llll}
\textit{something }&\textit{varies inversely to }&\textit{something else}\\ \quad \\
\textit{something }&=\cfrac{(\textit{some value })}{\textit{something else}}\\ \quad \\
y&=\cfrac{(n)}{x}
\end{array}\\ \quad \\
x=8\qquad y=6\\ \quad \\
\implies y=\cfrac{(n)}{x}\implies 6=\cfrac{n}{8}\)
find "n" first
OpenStudy (jdoe0001):
once you find "n", plug it back in \(\bf y=\cfrac{(n)}{x}\) along with the given "x" value to find "y"
OpenStudy (lovelyanna):
its A?
OpenStudy (jdoe0001):
dunno... what did you get?
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jigglypuff314 (jigglypuff314):
correct :)
OpenStudy (lovelyanna):
you know.. I thought that was the answer the first time.. don't know what changed O.o
OpenStudy (lovelyanna):
oh, and thanks :)
jigglypuff314 (jigglypuff314):
glad we could help :)
jigglypuff314 (jigglypuff314):
i gtg ttyl :)
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