Question

what happens when you cut the frequency of a tuning for in half?

Answer 1

Could you clarify the question?

Answer 2

If you used a tuning for with "half" the frequency, how many cycles would appear on the screen in 0.05 seconds? would the wavelength of this was be greater or smaller than the wavelength of the first turning fork> 16 is the original number of cycles

Answer 3

Ok, so frequency is the number of cycles per unit time.

Wavelength is
\[\lambda = \frac{c}{f}\]
where c is the wave speed, f is frequency.

Does that help?

Answer 4

We just started waves today and the sub (Teacher just had his first kid so hes with his wife for a bit) hasn't shown us any thing like that yet

Answer 5

Ok, well the only two things you need to know for this question are:

number of cycles in a fixed time is proportional to frequency

frequency is inversely proportional to wavelength

Answer 6

so one the paper it has a graph it has 16 cycle originally in a 0.05 second stop so to find the frequency would the equation be \[#of crycles \div time\] and then thatd be \[16\div0.05=320hz \] right?

Answer 7

Yeah

Answer 8

if i cut the frequency in half would the number of cycles go down to 8? and the wave length would be smaller right?

Answer 9

You're right about the number of cycles, but if
\[\lambda \propto \frac1f\]
do you think that wavelength will be smaller with a lower frequency?

Think what happens when you make the denominator of a fraction bigger: does the fraction equal a larger or a smaller number?

Answer 10

i get now thank you :3

Answer 11

One last thing; how would you draw a room with no air?