Question

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Answer 1

\[\Large f(x)=-2x-3\]The domain is given to be:\[\Large \{-4,\;-2,\;0,\;1.5,\;4\;\}\]These are the x values we're allowed to plug into our function.
What do you get when you plug -4 into the function?\[\Large f(-4)=-2(-4)-3\quad=\quad ?\]

Answer 2

You get -4?

Answer 3

Hmm I think you get 5.
-4 times -2 gives us positive 8.
then 8 minus 3 is 5.

So that gives us the first value for our range.\[\Large \{5,\;\}\]

Answer 4

To get the other values of the range, you simply plug in each of the domain values one at a time.

Answer 5

i still dont get it

Answer 6

but for number 11 the answer is 5?

Answer 7

No.
Question 11 is saying, "Here are a set of numbers you need to plug into f(x),
When you plug them in, what set of numbers does the function give us?"

So the number -4 when put into the function gave us 5.
The number -2 will give us another value.
0 will give us another... and so on.

Answer 8

These values that are getting pumped out collectively make up our range.

Answer 9

\[\Large f(\color{#DD4747 }{x})\quad=\quad -2(\color{#DD4747 }{x})-3\]

\[\Large f(\color{#DD4747 }{-2})\quad=\quad -2(\color{#DD4747 }{-2})-3\]So what does f(-2) give you?

Answer 10

Try number 13 maybe, it's a little easier.\[\Large\bf\sf A(\color{#DD4747 }{n})\quad=\quad 2+(\color{#DD4747 }{n}-1)(-2.5)\] `Find the second term of the sequence`.
So the second term of the sequent corresponds to n=2.\[\Large\bf\sf A(\color{#DD4747 }{2})\quad=\quad 2+(\color{#DD4747 }{2}-1)(-2.5)\]

Answer 11

Do you understand how to simplify that?

Answer 12

hold on let me see if i can find this question outside this box

Answer 13

ok thanks @satellite73

Answer 14

ok now which problem are you doing?

Answer 15

all of them.

Answer 16

we have in one of them \(f(x)=5x^2+4\) right?

Answer 17

yes

Answer 18

and a domain of \(\{-4,-2,0,1.5,4\}\) yes?

Answer 19

yep

Answer 20

your job is then to compute 5 numbers:
\[f(-4),f(-2),f(0),f(1.5),f(4)\] do you know how to do that?

Answer 21

no i dontt

Answer 22

\[f(x)=5x^2+4\]\[f(-4)=5(-4)^2+4\]

Answer 23

how about that, can you compute that number?

Answer 24

how do i do that though

Answer 25

square \(-4\) i.e. compute \(-4\times -4\) what do you get?

Answer 26

16 right?

Answer 27

right

Answer 28

so first step is
\[f(-4)=5(-4)^2+4=5\times 16+4\]
now what is \(5\times 16\) ?

Answer 29

80

Answer 30

got is
second step is
\[f(-4)=5(-4)^2+4=5\times 16+4=80+4\] your last job is to compute \(80+4\)

Answer 31

84

Answer 32

ok good
so we have \[f(-4)=5(-4)^2+4=5\times 16+4=80+4=84\] or
\[f(-4)=84\]
on to the next one

Answer 33

is it the answer for the first one?

Answer 34

\[f(x)=5x^2+4\]
\[f(-2)=5\times (-2)^2+4\] go ahead and complete that, we have 3 more after

Answer 35

let me know what you get

Answer 36

how do i start this?

Answer 37

same as the last one, but this time with \(-2\) instead of \(-4\)

Answer 38

square \(-2\)
multiply the result by \(5\)
then add \(4\)

Answer 39

9

Answer 40

what is \((-2)^2\)?

Answer 41

4

Answer 42

ok, now multiply it by 5
what do you get?

Answer 43

20

Answer 44

then add 4

Answer 45

24

Answer 46

whew
so \(f(-2)=24\)
3 more to go

Answer 47

how about \(f(0)=5\times 0^2+4\)?

Answer 48

wait which one are we on?

Answer 49

we are still on the same problem

Answer 50

oh

Answer 51

how do i start this one now

Answer 52

\[f(x)=5x^2+4\]find the range if the domain is \[\{-4,-2,0,1.5,4\}\] we have to compute 5 numbers, so far we only have \(f(-4)=84\) and \(f(-2)=24\)
we still need \(f(0)\) etc

Answer 53

how do i do that

Answer 54

same way you did the other two
square 0, multiply the result by 5, add 4

Answer 55

what do i multiply 5 by?

Answer 56

what is \(0^2\)?

Answer 57

2, or you mean 5 multiply 2?

Answer 58

can you give me answer for like two of them

Answer 59

@satellite73

Answer 60

what is zero times zero ?

Answer 61

0

Answer 62

and what is \(5\times 0\) ?

Answer 63

0 too

Answer 64

i need it due soon:(

Answer 65

?