Using the transformation T: (x, y) (x + 2, y + 1), find the distance AB
@helpme1.2 @satellite73
distance formula \[\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]
okay so you would do those transformations based on the coordinates right? Then by using the distance formula, you can figure out the distance between A and B. So I believe that transformation is a dilation. :)
so take the point of AB and plug it in the formula above and solve
Sorry, I was away from the computer. So I plug in (0,0) and (1,3)?
I don't understand!!! how does the question relate to the transformation??? If it is "find the distance A'B'" , It makes sense to me. To find AB, we do nothing with the transformation :(
I have to use the transformation to get AB
A, B are given, no need to use transformation to get it, right? just apply distance formula!!
No.. I have A and B, but I need AB
ok, so I am sorry, I don't know !! @Luigi0210
Lol, no worries.
@nikato
Don't u just use the distance formula?
Wait, the original A and B, or the transformed one?
If original plug in (0,0) and (1,3) If after transformation (2,1) and (3,4)
It tells me to use that transformation. :/ I thought I just had to plug in (0,0) (1,3) into the transformation. .-.
U could do that, but they also transformed it for u in the picture.
The letter with the apostrophe is the point after the transformation
I think it's the original one. (0,0) and (1,3) If they told u to do the transformation, they would have told u to find the distance of A'B'
But... they DID tell me to find the distance of AB
Yes. And based on ur diagram A=(0,0) B=(1,3) and now use the distance formula to find the distance
translations are isometries and preserve distance
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