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Mathematics 15 Online
OpenStudy (anonymous):

Find the solution set Problem in comments

OpenStudy (anonymous):

\[\LARGE x^2+14x+49=0\] @mathmale

OpenStudy (mathmale):

Aha: a factoring problem. Which of the following methods are you most comfortable with? (a) direct factoring based on the knowledge that 49 factors out to 7*7 or (-7)(-7); (b) quadradic formula, (c) graphing; (d) completing the square? We could go through any of those; your choice.

OpenStudy (anonymous):

A seems to be the easiest, or is there an easier method? =]

OpenStudy (mathmale):

(a) is the easiest, yes! :) Think: x^2 + 14x + 49 = two binomial (two-term) factors, each with x and each with 7 in it: (x+7)(x+7). You can check the correctness of this result by using the FOIL method to multiply out (x+7)(x+7).

OpenStudy (mathmale):

This is a relatively easy problem. If you'd like to discuss a harder one, then by all means post it.

OpenStudy (anonymous):

So the solution set is {7,7}?

OpenStudy (anonymous):

Never mind, it's -7 :D. Thanks! :)

OpenStudy (mathmale):

Actually, you were right the first time: The solution set is indeed {7, 7}. You have TWO solutions which happen to be identical. (That's OK.)

OpenStudy (anonymous):

Oh it just told me "-7" was correct and {7,7} was not correct O_o strange?

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