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Mathematics 13 Online
OpenStudy (anonymous):

When looking at a rational function, Charles and Bobby have two different thoughts. Charles says that the function is defined at x = −2, x = 3, and x = 5. Bobby says that the function is undefined at those x values. Describe a situation where Charles is correct, and describe a situation where Bobby is correct. Is it possible for a situation to exist that they are both correct? Justify your answer.

OpenStudy (lucaz):

when Bobby is correct the function looks like this \[\frac{(any~expression)}{(x+2)(x-3)(x-5)}\] that's undefined for x={-2, 3, 5} when Charles is correct the denominator cannot be zero when x={-2, 3, 5}, so it cannot have any of the three parentheses from the undefined function in the denominator, anything else is defined for x={-2, 3, 5}

OpenStudy (anonymous):

Omg, Thank you so much

OpenStudy (lucaz):

no problem

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