Question

A girl moves down the hall at 1.2 m/s When she sees Peter coming, he begins to run is fear. After 3.2s he is moving 3.6m/s what is his acceleration?

Answer 1

u=1.2m/s
v=3.6 m/s
t=3.2 s
v=u+at
plug the values and find the value of a

Answer 2

what?

Answer 3

I do not get this

Answer 4

3.6=1.2+3.2a
3.6-1.2=3.2a
2.4/3.2=a
or a=2/3m/s^2

Answer 5

so what would the answer be

Answer 6

\[acceleration~is \frac{ 2 }{3 }m/s ^{2}\]

Answer 7

I do not get this how you found out this

Answer 8

correction
\[It~is \frac{ 3 }{ 4 }m/s ^{2}\]

Answer 9

How did you find out this

Answer 10

could you draw it out

Answer 11

it is a general formula in physics.

Answer 12

what is the formula

Answer 13

rate of change of velocity is called acceleration.
Let initial velocity =u
time=t
velocity after time t=v
change of velocity=v-u
\[Rate~of~change~of~velocity=\frac{ v-u }{t }\]
rate of change of velocity is called acceleration.
\[Hence~a=\frac{ v-u }{ t },~or~v-u=at,~or~v=u+at\]

Answer 14

oh ok thank you so much you saved my life :)

Answer 15

np