Question

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Answer 1

0.140 kgm/s

Answer 2

ok there u go

Answer 3

my bad worng question

Answer 4

Impulse is a change in momentum p
\[\Delta\vec{p} = \vec{F}\times\Delta t\]
So you did the right thing to multiply force by time interval.
0.08 Ns is indeed the right answer.

Answer 5

By the way if you have force that varies over time from t1 to t2
\[\Delta\vec{p} = \int^{t_2}_{t_1} \vec{F}(t) dt\]

Answer 6

\[\vec{p}=m\vec{v}\]

Answer 7

Yeah,\[1\,600\times24=38\,400\]
Rounding, I guess.

Answer 8

All answers are true in of themselves. B and C seem to be identical to each other.

I think the impulse-momentum theorem is simply

\[\vec{J} = \Delta\vec{p}\]

where J is impulse.

In words: "Impulse is the change in momentum"

So... all of B, C and D?

Maybe just D, since that seems to explicitly relate impulse to momentum?

Answer 9

Every source I can find explains the impulse-momentum theorem that way.
I think the question is badly written :/

Answer 10

Probably D because that's the only one that relates impulse to momentum