What is the equation of the parabola, in vertex form, with vertex at (-2,-4) and directrix x = -6?
|dw:1389297658513:dw| \(\begin{array}{rllll} 4{\color{red}{ p}}(y-&{\color{red}{ k}})=(x-&{\color{red}{ h}})^2\\ \ \ \uparrow &\uparrow &\uparrow \\ \textit{focus distance}&\textit{vertex-y coord}&\textit{vertex-x coord} \end{array}\)
woops ... my arrow ... went awry... anyhow
\(\begin{array}{llll} 4{\color{red}{ p}}(y-&{\color{red}{ k}})=(x-&{\color{red}{ h}})^2\\ \ \uparrow &\uparrow &\uparrow \\ \textit{focus distance}&\textit{vertex-y coord}&\textit{vertex-x coord} \end{array}\)
you pretty much have all those values given...so, plug them in :)
I'm confused..whats the focus distance?
the distance from the vertex to the focus which is also the same as the vertex to the directrix so.. how many units from the vertex to the directrix?
-6?? @jdoe0001
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