Which of the following quartic functions has x=-1 and x=-4 as its only two real zeros?

Question

anonymous · Answer

The answer will be whatever equation can be separated so that x = -1 and x = -4

For example, if the equation had (x+4) then that would be correct
This is because x + 4 = 0
                       x = -4

campbell_st · Answer

well use the factor theorem to test

find 

f(-1) and f(-4)   both should equal zero.

anonymous · Answer

Correct campbell_st

If plugging the two values into the equation do not solve to 0, then the answer is incorrect.
You are looking for f(-1) and f(-4) to equal 0

campbell_st · Answer

which means

f(-1) = 0

f(-4) = 0

and there will be 2 other zeros, if its a quartic function

anonymous · Answer

$$y=x ^{4}-4x ^{3}-4x ^{2}-4x-3 $$
$$y=-x ^{4}+4x ^{3}+4x ^{2}+4x+3$$
$$y=x ^{4}+4x ^{3}+3x ^{2}+4x-4$$
$$y=x ^{4}+4x ^{3}+4x ^{2}+4x+3$$

campbell_st · Answer

thanks @KirbyLegs glad you agreed with my method

anonymous · Answer

Thanks.

anonymous · Answer

In order for it to equal 0, you would have to have some subtraction to lower the big numbers.

Trying plugging in to A and see what you get.

anonymous · Answer

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