Question

Simplify. Cubed root of x^-1y^-2

Answer 1

hmm not sure is simplifyable

Answer 2

\(\Large \bf \sqrt[3]{x^{-1}y^{-2}}\) looks very simplified

Answer 3

got any choices?

Answer 4

No sir. They might have slipped in a trick question though. Thanks

Answer 5

trick or treat! =)

Answer 6

you can change it... to a rational exponent or say a rational radicand with a rational exponent

but that'd not be simplified per se

Answer 7

lemme poke it.... a bit

Answer 8

\(\bf \large { a^{-{\color{red} n}} = \cfrac{1}{a^{\color{red} n}}\qquad \qquad a^{\frac{{\color{blue} n}}{{\color{red} m}}} = \sqrt[{\color{red} m}]{a^{\color{blue} n}}\\ \quad \\ \quad \\
\sqrt[3]{x^{-1}y^{-2}}\implies \sqrt[3]{\cfrac{1}{x^1}\cfrac{1}{y^2}}\implies \sqrt[3]{\cfrac{1}{x}} \sqrt[3]{\cfrac{1}{y^2}}\implies \cfrac{\sqrt[3]{1}}{\sqrt[3]{x}}\cdot \cfrac{\sqrt[3]{1}}{\sqrt[3]{y^2}}\\ \quad \\
\cfrac{1}{\sqrt[3]{x}}\cdot \cfrac{1}{\sqrt[3]{y^2}}\implies
\cfrac{1}{x^{\frac{1}{3}}}\cdot \cfrac{1}{y^{\frac{2}{3}}}\implies \cfrac{1}{x^{\frac{1}{3}}y^{\frac{2}{3}}}}\)

Answer 9

\(\Large \bf \cfrac{1}{x^{\frac{1}{3}}y^{\frac{2}{3}}}\implies \cfrac{1}{\sqrt[3]{xy^2}}\)

Answer 10

then again... not a simplified version per se