solve: d = ut + 0.5at^2 I dont understand... help?
This is a physics formula for distance.
yes, but i need to solve it as a literal equation
u in this case stands for velocity, t stands for time, and (a) stands for acceleration. Simply plug your values into this equation and you will get the distance that something has traveled.
i forgot to say to solve for "a"
Do you understand how to change this formula around with algebra?
i dont think so..
What would happen if you moved the ut to the other side of the equation?
would it be utd?
Not quite, it would be d - ut = .5at^2
oh ok, but what would i do next?
What is the opposite of multiplying something?
dividing right?
Very good
so i divide both sides of the equation by... is it .5?
That is the first step but we can do more than that. We can divide both side .5t^2 so that we get a by itself.
so it would be .5^2/d-ut?
When we divide both sides of the equation by .5t^2 it cancels the .5t^2 on the right side but how does the equation look like on the left? You are switched around on your equation above
ut-d/.5t=a?
That is almost perfect but your .5t is missing something
is it the exponent ^2?
Correct
is the equation done now?
You have your d and ut in the wrong place. d-ut is what is should be
show me your final answer and I will tell you if it is correct.
so d is before ut? so it would look like d-ut/o.5t^2=a?
Very good that is the correct answer
Thank you so much!!
You're welcome
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