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Mathematics 24 Online
OpenStudy (anonymous):

solve: d = ut + 0.5at^2 I dont understand... help?

OpenStudy (anonymous):

This is a physics formula for distance.

OpenStudy (anonymous):

yes, but i need to solve it as a literal equation

OpenStudy (anonymous):

u in this case stands for velocity, t stands for time, and (a) stands for acceleration. Simply plug your values into this equation and you will get the distance that something has traveled.

OpenStudy (anonymous):

i forgot to say to solve for "a"

OpenStudy (anonymous):

Do you understand how to change this formula around with algebra?

OpenStudy (anonymous):

i dont think so..

OpenStudy (anonymous):

What would happen if you moved the ut to the other side of the equation?

OpenStudy (anonymous):

would it be utd?

OpenStudy (anonymous):

Not quite, it would be d - ut = .5at^2

OpenStudy (anonymous):

oh ok, but what would i do next?

OpenStudy (anonymous):

What is the opposite of multiplying something?

OpenStudy (anonymous):

dividing right?

OpenStudy (anonymous):

Very good

OpenStudy (anonymous):

so i divide both sides of the equation by... is it .5?

OpenStudy (anonymous):

That is the first step but we can do more than that. We can divide both side .5t^2 so that we get a by itself.

OpenStudy (anonymous):

so it would be .5^2/d-ut?

OpenStudy (anonymous):

When we divide both sides of the equation by .5t^2 it cancels the .5t^2 on the right side but how does the equation look like on the left? You are switched around on your equation above

OpenStudy (anonymous):

ut-d/.5t=a?

OpenStudy (anonymous):

That is almost perfect but your .5t is missing something

OpenStudy (anonymous):

is it the exponent ^2?

OpenStudy (anonymous):

Correct

OpenStudy (anonymous):

is the equation done now?

OpenStudy (anonymous):

You have your d and ut in the wrong place. d-ut is what is should be

OpenStudy (anonymous):

show me your final answer and I will tell you if it is correct.

OpenStudy (anonymous):

so d is before ut? so it would look like d-ut/o.5t^2=a?

OpenStudy (anonymous):

Very good that is the correct answer

OpenStudy (anonymous):

Thank you so much!!

OpenStudy (anonymous):

You're welcome

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