Question

What is the standard form of the equation of a circle with its center at (2, -3) and passing through the point (-2, 0)?

Answer choices:
(x − 2)2 + (y + 3)2 = 5

(x + 2)2 + (y − 3)2 = 25

(x − 2)2 + (y + 3)2 = 25

(x − 2)2 − (y + 3)2 = 5

Answer 1

First, what is the standard equation for a circle with it's center at (0,0)?

Answer 2

(2, -3)

Answer 3

I will help you, but you must help you too.

Answer 4

Thats all the question is asking for.

Answer 5

the circle in your problem does not sit with it's center at (0,0) but at (2, -3).
I am wondering if you know what it should look like before being shifted.

Answer 6

I need to know where to start helping

Answer 7

Well I have (x-a)(x+a)+(y-b)(y+b)=m2
I dont know if that will help with anything but that whati have so far.

Answer 8

-a shifts center to right
a shifts center to left
b shifts center down
-b shifts center to up
since your circle's center is at (2,-3), then you should have (x-2)^2
and (y+3)
Your problem states that it passes through (-2,0) so use these two numbers in place of x and y to solve your equation