Question

Write each expression as a single logarithm.
Log\/3 24 + Log\/3 2

Answer 1

\(\log_{3}{24}+\log_{3}{2}=\log_{3}{24 \cdot 2}=\log_{3}{48}\)

Answer 2

Sorry I don't know why the two is so high. It's suppose to be even with the rest of it besides the three's

Answer 3

Oh! Thank you! That's a lot easier than how It was explained to me. Thank you!

Answer 4

your welcome! :)

Answer 5

What do you do if it is like this 3 Logx + 5 Logy

Answer 6

First, by the power rule, \(3\log{x}+5\log{y}=\log{x^3}+\log{y^5}\). Then proceed as before.

Answer 7

Then you multiply 3 * 5?

Answer 8

Nope. You must multiply \(x^3\) and \(y^5\), something like \(\log{x^3 y^5}\).

Answer 9

You cannot multiply 3 and 5, since their bases, x and y, are not the same.

Answer 10

So after you multiply them what do you do? Because wouldn't you still have x and y left

Answer 11

That's the answer. x and y are not the same, so you cannot combine the two together. You can just put it side by side, like \(\log_{5}{x^4 y^7 z^9}\).

Answer 12

So it would just be logx\[Logx ^{3}y ^{5} \] That's the answer?

Answer 13

yes. :)

Answer 14

Oh! Okay thanks again.