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@AnImEfReaK
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\[3^{x+1} = \frac{ 27 }{ 3^{x} }\]
Simplify 27 it is 3^ ?
3
well rewrite it in index form using index laws \[27 = 3^3....so.... \frac{27}{3^x} = 3^{3 - x}\] so equate the powers again x + 1 = 3 - x solve for x
\(\dfrac{3^3}{3^x}\)
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Can you simplify that?
yh
So it would be?
3/ x
So use the powers, as all the 3's are the same.
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ahan so the answer is 1 ?
\(x-1=\dfrac {3}{x}\)
@AnImEfReaK nd @campbell_st did u guys got x=1 as an answer ?
yes thats the answer, and you can check by substituting...
thank you guys
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Yeah x-1=3-x 2x=2 x=1.
That's correct :)
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