Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (rane):

@AnImEfReaK

OpenStudy (rane):

\[3^{x+1} = \frac{ 27 }{ 3^{x} }\]

OpenStudy (anonymous):

Simplify 27 it is 3^ ?

OpenStudy (rane):

3

OpenStudy (campbell_st):

well rewrite it in index form using index laws \[27 = 3^3....so.... \frac{27}{3^x} = 3^{3 - x}\] so equate the powers again x + 1 = 3 - x solve for x

OpenStudy (anonymous):

\(\dfrac{3^3}{3^x}\)

OpenStudy (anonymous):

Can you simplify that?

OpenStudy (rane):

yh

OpenStudy (anonymous):

So it would be?

OpenStudy (rane):

3/ x

OpenStudy (anonymous):

So use the powers, as all the 3's are the same.

OpenStudy (rane):

ahan so the answer is 1 ?

OpenStudy (anonymous):

\(x-1=\dfrac {3}{x}\)

OpenStudy (rane):

@AnImEfReaK nd @campbell_st did u guys got x=1 as an answer ?

OpenStudy (campbell_st):

yes thats the answer, and you can check by substituting...

OpenStudy (rane):

thank you guys

OpenStudy (anonymous):

Yeah x-1=3-x 2x=2 x=1.

OpenStudy (anonymous):

That's correct :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!