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3^x^3=9^x
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Mind re-typing this problem, preferably with ( )? 3^x^3 is very ambiguous.
well rewrite 9^x as a power of 3 \[9^x = (3^2)^x ... or.... 3^{2x}\] using log laws power of a power now you have the same base, you can equate the powers \[3^{x^3} = 3^{2x}\] so you can say \[x^3 = 2x\] now solve for x... and its interesting, @jinxhead... seems to have left out a solution...
another answer is suppose to be 0. how do you get that
well set the equation to zero by subtracting 2x from both sides \[x^3 - 2x = 0\] now factor the equation \[x(x^2 - 2) = 0\]
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