Question

2^y x 8^-y = 4^y

Answer 1

1. When you see exponents with different bases, make them the same base. (Notice that 4=2^2 and 8=2^3)

Answer 2

Do that first, what do you get? :)

Answer 3

2^y x (2^3)^-y = (2^2)^y

Answer 4

Now, use the law of indices: \(\Large (a^b)^n=a^{bn}\)

Answer 5

2^y x 2^-3y = 2^2y

would that be

2^-2y = 2^2y ?

Answer 6

yes, you're getting it so fast :)

Answer 7

Now use this law of indices: \(\Large a^{-n}=\frac1{a^n}\)

Answer 8

\[\frac{ 1 }{ 2^{2y} } = 2^{2y}\]

Answer 9

Now leave the 1 in the LHS and move the other stuffs to the RHS :)

Answer 10

\[1 = 2^{4x ^{2}}\]

Answer 11

Where did you get the x^2 lol

Answer 12

i meant y. sorry

Answer 13

lolz yep, now notice that \(1=2^0\)

Answer 14

ohhhh